How would I go about converting two moles of potassium bromide/KBr into grams? I got the answer of 171.42. (..grams?) Is this correct?
Here's the original problem:
What mass of Potassium Bromide is produced by the reaction of 2.65 moles of Calcium Bromide with excess potassium?
Balanced Equation: 2K + CaBr2----> 2KBr + Ca