# [SOLVED] Chem 1000: Specific Heat problem

• Apr 12th 2009, 03:22 PM
ninobrn99
[SOLVED] Chem 1000: Specific Heat problem
Folks,
Im not understanding how to find the specific heat of something. The books examples are a bit confusing! Could someone please break it down for me?

Here's the problem:
Assuming that Coca-Cola has the same specific heat as water, how much energy in calories is removed when 350g of coke is cooled from room temp (25 degrees C) to refrigerator temp (3*C)?
• Apr 12th 2009, 04:02 PM
Referos
Specific heat is the amount of energy needed to heat 1 gram of a substance by 1 C. The specific heat of water is 1 cal/g*C. That means, if you give, say, 1 cal as heat to 10 grams of water, its temperature will increase by 0.1 C.
You should have see this formula in your physics/chemistry class:

\$\displaystyle Heat = m*c*\Delta T\$

where m is the mass in g, c is the specific heat, and \$\displaystyle \Delta T\$ is the temperature differential in C.

Replace the variables in the formula and you have the solution to your problem (remember, the temperature differential is negative, since the water looses heat!).
• Apr 12th 2009, 04:26 PM
e^(i*pi)
To add to Referos answer the specific heat of water is 4.18 kJ/(kg K) if you're using SI units
• Apr 13th 2009, 08:59 AM
ninobrn99
So is this correct?
3.2186x10^4
I used Referos formula and the specific heat that e^(i*pi) gave me:
350*4.18*22
• Apr 13th 2009, 09:08 AM
e^(i*pi)
Quote:

Originally Posted by ninobrn99
So is this correct?
3.2186x10^4
I used Referos formula and the specific heat that e^(i*pi) gave me:
350*4.18*22