Q- Find the sum of the series? 1/(2^1/2 + 1^1/2) + 1/(2^1/2 + 3^1/2) + ......... + 1/(120^1/2 + 121^1/2) Any help would be greatly appreciated. Thanks, Ashish
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Write 1 = sqrt(2)^2 - sqrt(1)^2 1 = sqrt(3)^2 - sqrt(2)^2 1 = sqrt(4)^2 - sqrt(3)^2 . . . . Remember that sqrt(a)^2 - sqrt(b)^2 ={sqrt(a) - sqrt(b)} x {sqrt(a) + sqrt(b)} Use this formula for each term many things will be cancelled .. ..
Originally Posted by a69356 Q- Find the sum of the series? 1/(2^1/2 + 1^1/2) + 1/(2^1/2 + 3^1/2) + ......... + 1/(120^1/2 + 121^1/2) Any help would be greatly appreciated. Thanks, Ashish Note that . You series is then Write out several terms to see what is going to happen.
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