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Math Help - Motion And Force

  1. #1
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    Motion And Force

    Can anyone tell me how to do Q 41 and 42..
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  2. #2
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    Quote Originally Posted by siddscool19 View Post
    Can anyone tell me how to do Q 41 and 42..
    Q41 You should equate kinetic energy to potential energy so as the ball obtain enough kinetic energy to climb the largest circle (D=6R):



    Q42 If mass is distributed equally along the length, then after swap potential energy of rope with mass m is decreased by mgl and of rope with mass 3m is increased by 3mgl.
    Last edited by CaptainBlack; April 3rd 2009 at 05:24 AM. Reason: removed actual answers
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  3. #3
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    Quote Originally Posted by siddscool19 View Post
    Can anyone tell me how to do Q 41 and 42..
    41. The minimum velocity (assuming negligable friction) corresponds to a KE equal to the potential energy of the particle when at the higest point of the tube.

    CB
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  4. #4
    Grand Panjandrum
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    Quote Originally Posted by siddscool19 View Post
    Can anyone tell me how to do Q 41 and 42..
    42. You have raised a mass of 3m through l and lowered a mass of m through a distance l, so the potential energy change is the same as though you had raised a mass of 2m through a distance l.

    CB
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