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Math Help - Dilution Help Please! (M1V1=M2V2) *CHEMISTRY*

  1. #1
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    Unhappy Dilution Help Please! (M1V1=M2V2) *CHEMISTRY*

    Okay, so I got this homework yesterday and Im not quite clear on how to do this.
    I have problems such as

    If I dilute 250mL of 0.10M Lithium acetate solution to a volume of 750mL, what will the concentration of this solution be.

    Can someone help me with this problem? This is how far I got

    M1 = ?
    V1 = 250mL
    M2 = 0.10M
    V2 = 750mL
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  2. #2
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    Quote Originally Posted by Metallica92 View Post
    Okay, so I got this homework yesterday and Im not quite clear on how to do this.
    I have problems such as

    If I dilute 250mL of 0.10M Lithium acetate solution to a volume of 750mL, what will the concentration of this solution be.

    Can someone help me with this problem? This is how far I got

    M1 = ?
    V1 = 250mL
    M2 = 0.10M
    V2 = 750mL
    As you will have the same number of moles you can say that {M_1V_1}={M_2V_2}
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  3. #3
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    Yes your set up is right. Remember, the moles of the solution does not change when you dilute it (with water) and that is why the equation holds.

    So plug it all into the equation and solve. Keep in mind the M stands for \tfrac{\text{mol}}{{\color{red}L}} so you must change units accordingly.
    Last edited by mr fantastic; April 5th 2009 at 05:07 PM. Reason: Removed reference to bumping
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  4. #4
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    WOA WOA WOA.....u guys are making it way to complicated, all you have to do is solve the proportion, thus M1 x V1 / V2 = M2.....thats it !!!

    So the answer should be .1(.25)/.75 = .033M
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  5. #5
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    But that's what we said... all we added was that the units must stay consistent.
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