Thread: Solving Simulataneous equations derived from 2d Concurrent Forces

Hey Guys,
After analysing a 2d Concurrent Force system I have found the 2 following equations. The question asks to find the value of x and I am unsure of what is the simpliest, hassle free method to do this. The question is posed in an assignment, however no working is required and use of a computer is fine.

Sum of Forces in Horizontal:
197cos(x) - 210cos(y) = 0

Sum of Forces in Vertical:
197cos(x) + 210sin(y) = 139

Find x.

Thanks Guys!

Originally Posted by holmesb

Hey Guys,
After analysing a 2d Concurrent Force system I have found the 2 following equations. The question asks to find the value of x and I am unsure of what is the simpliest, hassle free method to do this. The question is posed in an assignment, however no working is required and use of a computer is fine.

Sum of Forces in Horizontal:
197cos(x) - 210cos(y) = 0

Sum of Forces in Vertical:
197cos(x) + 210sin(y) = 139

Find x.

subtract the horizontal equation from the vertical equation, term for term ...

197cos(x) + 210sin(y) = 139
-[197cos(x) - 210cos(y) = 0]
------------------------------
210sin(y) + 210cos(y) = 139

sin(y) + cos(y) = 139/210

solve for y, then go back to either original equation and solve for x.