Thread: Need help with Kinematics !

Hi can everyone help me solve this exercise !

A particle moves in a straight line so that its position x m from a fixed point O on the line at any time t is give by X=t^3 -12t .

a. its velocity and acceleration at any time t
b. Its initial velocity and acceleration.

Thanks You

Position, velocity and acceleration stand in a direct relation.
If you have the function that describes the position, then the derivate of that function will give you the function of the velocity. The derivate of the velocity function will give you the acceleration.

So that you get here:

X= t^3 - 12t
V= 3t^2- 12
A= 6t

For finding the initial values, just insert t=0 if you suppose that the initial moment is when t=0.

That's great ...thanks you ...But what kind of this methods use to sole this equation ...can u tell me ...or give me the general formular for this...

Do you mean the formulas for the derivation of the function or the methods to find the zeros of the functions?

Yes , i mean the formulas for the derivation of the function ...thanks for you reply ...

Look at the following pdf file. It's pretty complete.