Why does i equal the square root of -1 and i^2 equal -1?
negative numbers got their start.)
There is a lot of math, science, and engineering that couldn't happen nowadays, had this number not been invented.
When you study complex numbers (numbers with the in them or involving taking the square root of negative values), make sure you remember the new rule: Always take care of the negative inside the square root first, before doing any other computations or simplifications!
(note I describe the complex numbers as constructed as they are built to have the properties needed so that certain algebraic process that we need make sense.)
The "construction" CaptainBlack refers to is this: Define the complex numbers to be the set of pairs of real numbers (a, b) with addition defined by (a,b)+ (c,d)= (a+c,b+d), (a,b)*(c,d)= (ac-bd,ad+bc). Since (a,0)+ (c,0)= (a+c,0) and (a,0)*(c,0)= (ac-0(0),a(0)+0(c))= (ac,0), we can identify the complex numbers of the form (a,0) with the real numbers. Now, (0,1)*(0,1)= (0(0)-1(1),0(1)+1(0))= (-1, 0) which we associate with -1.
If we represent (0,1) by i, and, as I said, (1,0) by 1, we have (a,b)= a(1,0)+ b(0,1)= a+ bi. And, then, .