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Math Help - centripetal force

  1. #1
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    Post centripetal force

    A body of mass 12 kg moves in a (counterclockwise) circular path of radius 11 meters centered at the origin, making one revolution every 10 seconds. We assume the circle is in the xy-plane, and so the third component may be ignored. At time t=0 the body is in the rightmost position (position with the largest x).
    A. Compute the centripetal force acting on the body at time t.
    ,
    B. Compute the magnitude of that force. = 52.11


    i found part B, but i have no idea how to solve part A
    Last edited by DMDil; March 19th 2009 at 03:17 PM.
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  2. #2
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    position of the mass at any time t ...

    \vec{r} = 11\cos\left(\frac{\pi}{5}t\right) \, \vec{i} + 11\sin\left(\frac{\pi}{5}t\right) \, \vec{j}

    centripetal force ...

    \vec{F_c} = m\vec{a} = m \frac{d^2 \vec{r}}{dt^2}
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