1. ## [SOLVED] Surds

Q. simpify: $\sqrt a^3 + 2 \sqrt a$
the answer is $(a+2)\sqrt a$ but but i can't seem to figure out the solution.

thanks

2. Originally Posted by waven
Q. simpify: $\sqrt a^3 + 2 \sqrt a$
the answer is $(a+2)\sqrt a$ but but i can't seem to figure out the solution.

thanks

$a^{\frac{3}{2}}+2a^{\frac{1}{2}}$

Take out the common factor which is $a^{\frac{1}{2}}$

$a^{\frac{1}{2}}(a+2)$ which is similar the ans given.

$a^{\frac{3}{2}}+2a^{\frac{1}{2}}$

Take out the common factor which is $a^{\frac{1}{2}}$

$a^{\frac{1}{2}}(a+2)$ which is similar the ans given.
is $a^{\frac{1}{2}}$ the common factor because there are 2 $a^{\frac{1}{2}}$s?
and
would it still be the same answer it it was $\sqrt a(a+2)$ rather than $(a+2)\sqrt a$

4. Originally Posted by waven
is $a^{\frac{1}{2}}$ the common factor because there are 2 $a^{\frac{1}{2}}$s?
and
would it still be the same answer it it was $\sqrt a(a+2)$ rather than $(a+2)\sqrt a$
yes .

note that ab = ba

$a^{\frac{3}{2}}+2a^{\frac{1}{2}}$
Take out the common factor which is $a^{\frac{1}{2}}$
$a^{\frac{1}{2}}(a+2)$ which is similar the ans given.
btw how did $a^{\frac{3}{2}}$ change to $(a+2)$
btw how did $a^{\frac{3}{2}}$ change to $(a+2)$
$a^{\frac{3}{2}} = a^{1 + \frac{1}{2}} = a \cdot a^{\frac{1}{2}}$.