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Math Help - Babylonian math

  1. #1
    Junior Member
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    Sep 2008
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    Babylonian math

    Hello everyone,

    Could someone please tell me if these conversions between Babylonian math and the decimal system are correct?

    3;30=3(1)+3(1/60)=3.5
    3.5=3;30 and 3;30=3.5

    12;15=12+15(1/60)=12.25
    12.25=12;15

    1,8;45=1(60)+8+45(1/60)=68.75

    1,9;45,22=1(60)+9(1)+45(1/60)+22(1/3600)=69.75

    69.75=1,9;45,22

    Thank you very much
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  2. #2
    Super Member

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    Lexington, MA (USA)
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    Hello, Chocolatelover2!

    Ya done real good . . .


    Are these conversions between Babylonian math and the decimal system correct?


    [3;30]_{60}\:=\:3(1)+3\left(\tfrac{1}{60}\right)\:=\:3.5 . Yes!


    [12;15]_{60}\:=\:12+15\left(\tfrac{1}{60}\right)\:=\:12.2  5 . Right!


    [1,8;45]_{60}\:=\:1(60)+8(1)+45\left(\tfrac{1}{60}\right) \:=\:68.75 . Correct!


    [1,9;45,22]_{60}\:=\:1(60)+9(1)+45\left(\tfrac{1}{60}\right)+  22\left(\tfrac{1}{3600}\right)\:=\:69.75 . . . . no

    Did you forget that last fraction?

    1(60) + 9(1) + 45\left(\tfrac{1}{60}\right) + 22\left(\frac{1}{3600}\right) \;=\;69.756111\hdots \;=\;69\tfrac{1361}{1800}

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