# Thread: Babylonian math

1. ## Babylonian math

Hello everyone,

Could someone please tell me if these conversions between Babylonian math and the decimal system are correct?

3;30=3(1)+3(1/60)=3.5
3.5=3;30 and 3;30=3.5

12;15=12+15(1/60)=12.25
12.25=12;15

1,8;45=1(60)+8+45(1/60)=68.75

1,9;45,22=1(60)+9(1)+45(1/60)+22(1/3600)=69.75

69.75=1,9;45,22

Thank you very much

2. Hello, Chocolatelover2!

Ya done real good . . .

Are these conversions between Babylonian math and the decimal system correct?

$\displaystyle [3;30]_{60}\:=\:3(1)+3\left(\tfrac{1}{60}\right)\:=\:3.5$ . Yes!

$\displaystyle [12;15]_{60}\:=\:12+15\left(\tfrac{1}{60}\right)\:=\:12.2 5$ . Right!

$\displaystyle [1,8;45]_{60}\:=\:1(60)+8(1)+45\left(\tfrac{1}{60}\right) \:=\:68.75$ . Correct!

$\displaystyle [1,9;45,22]_{60}\:=\:1(60)+9(1)+45\left(\tfrac{1}{60}\right)+ 22\left(\tfrac{1}{3600}\right)\:=\:69.75$ . . . . no

Did you forget that last fraction?

$\displaystyle 1(60) + 9(1) + 45\left(\tfrac{1}{60}\right) + 22\left(\frac{1}{3600}\right) \;=\;69.756111\hdots \;=\;69\tfrac{1361}{1800}$