1. ## Physics friction

1. The problem statement, all variables and given/known data
Find the normal force on an object, 80kg, which is being pulled up by a force of 4000N at an angle of: A) Up at 50 degrees. B) Down at an angle of 70 degrees.

2. Relevant equations
Fw = mg
Fsinx
Fcosx

3. The attempt at a solution

A) Fn = 784 - 4000sin50 = -2280 = 2280N

B) Fn = 784 + 4000sin70 = 4543N

Is this correct?

2. If F is force applied at an angle x with horizontal then, normal force (N) component and horizontal force (H) component can be calculated as $N = F * \sin(x)$ and $H = F * \cos(x)$

refer to attachment

Now just replace the value of F and angle x (remember its angle which forca makes with horizontal)
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