Hi, I'm trying to find the solution to but i can't for the life of me figure out how to do it, it's the square root that has me stumped. I've managed to get it into a form of and found the roots of approximately 5.5 and -6.5 which i then substituted into the y=mx+c form equations but still couldnt get the right answer of 4,2.
So I've returned again seeking help, anyone care to take a stab?
to be honest... no, i still can't. I suppose I should have put in more information in my original post, but that was one of the steps i went through to get to I suppose the real problem I'm having is when i get because i can't figure out how to bring it down to a single x term.
So we have y^2-y-6=0
This means that y=3 or y=-2
But x=y² (and not the contrary)
So x=9 or 4.
If you substitute in , 9 will work, but not 4, because
So 9 is a solution
I didn't understand this was for finding the intersection of two curves... So you want to find the intersection between y=sqrt(x) and y=x-6 ?
9,3 is the correct answer. And I checked it on a graph...
It would have been nice to put the whole problem ^^' to avoid confusion. And I'm sorry for the one I created.