Help with percentages..

**tgreaves** · February 20th 2009, 08:01 AM

Suppose I have the number 1000, I take 34% away from that which leaves me with 660..

Lets say I have the 660 and I know that 34% was removed from number x to give me that 660.. Whats the formula to get the original number(1000) given the number 660 and the 34%????

**ADARSH** · February 20th 2009, 08:09 AM

Originally Posted by tgreaves

Suppose I have the number 1000, I take 34% away from that which leaves me with 660..

Lets say I have the 660 and I know that 34% was removed from number x to give me that 660.. Whats the formula to get the original number(1000) given the number 660 and the 34%????

$ \frac{660\times 100}{x} = 34 $
therefore
$x= \frac{660 \times 100}{34}.....formula$

**tgreaves** · February 20th 2009, 10:33 AM

Originally Posted by ADARSH

$ \frac{660\times 100}{x} = 34 $
therefore
$x= \frac{660 \times 100}{34}.....formula$

I think im missing something here..

$\frac{660 \times 100}{34}$ does not = 1000..

**Air** · February 20th 2009, 11:35 AM

Originally Posted by tgreaves

Suppose I have the number 1000, I take 34% away from that which leaves me with 660..

Lets say I have the 660 and I know that 34% was removed from number x to give me that 660.. Whats the formula to get the original number(1000) given the number 660 and the 34%????

If you are told that $34\%$ is reduced then you are aware of the fact that the value remaining is $100\% - 34\% = 66\%$ . For example, the value of reducing $1000$ by $34\%$ is the same as having $65\%$ remaining.

Given $\frac{a}{b} = c\%$ where $a$ is the value remaining, $b$ is the original value and $c\%$ is the percentage. Therefore, with manipulation it can be deduced that $b = (100 \times a) / c$ .

For your example, $b = \frac{100 \times a}{c} \rightarrow x = \frac{100 \times 660}{66}$

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