1. Find the point where Y=x2+2x-4 crosses x axis:

When y = 0 the parabola is on the x axis so solve 0=x^2+2x-4

This equation is of the form ax^2 + bx + c

a=1

b=2

c=-4

To find the roots we use the quadratic equation:

plug and chug and you get -1+sqrt(5) and -1-sqrt(5)