Can someone tell me what a "first-order reaction" is in easy to understand terms please?

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- Feb 15th 2009, 10:49 AMs3aWhat is a "first-order reaction?"
Can someone tell me what a "first-order reaction" is in easy to understand terms please?

- Feb 15th 2009, 11:16 AMo_O
Say that we're given a chemical reaction: $\displaystyle A + B \to C + D$

And the rate of the reaction is given by: $\displaystyle r = k[A]^m [B]^n$

We say that the order of the reaction with respect to $\displaystyle A$ is $\displaystyle m$ and the order with respect to $\displaystyle B$ is $\displaystyle n$. The total order of the reaction is given by $\displaystyle m + n$.

One thing to note that $\displaystyle m$ and $\displaystyle n$ are determined**experimentally**. There's no way to predict the order without actually carrying out the experiment itself.

Now for specifics. A first-order reaction means that the rate of the reaction depends only on one of the reactants with order 1, i.e. $\displaystyle r = k[A]^1$

A common form is its integrated form: $\displaystyle \ln [A]_0 = -kt + \ln [A]$ where $\displaystyle [A]_0$ is the initial concentration of our reactant. - Feb 15th 2009, 02:20 PMs3a
You went a little ahead of my course by embedding ln into chemistry but I just wanted to ask the following word problem question:

"Consider the decomposition of N2)5 in carbon tetrachloride (CCl4) at 45**°**C.

2N205(soln)-->4NO2(g)+O2(g)

The reaction is first-order in N205, with the specific rate constant 6.08x10^(-4) per second. Calculate the reaction rate under these conditions.

a) [N2O5] = 0.2 mol/L"

Thanks! - Feb 15th 2009, 04:07 PMo_O
Since this is a first-order reaction, we know the rate is given by: $\displaystyle r = k[\text{N}_2\text{O}_5]$

We know the specific rate constant ($\displaystyle k = 6.08 \times 10^{-4} \ s^{-1}$) and we know $\displaystyle [\text{N}_2\text{O}_5]$.

So simply plug it all in.