How to rationalise trinomial surds? Such as 1/ root(2) + root(3) + root (5). Thanks.
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Originally Posted by anonymous_maths How to rationalise trinomial surds? Such as 1/ root(2) + root(3) + root (5). Thanks. $\displaystyle \dfrac1{(\sqrt{2}+\sqrt{3})+\sqrt{5}} \cdot \dfrac{(\sqrt{2}+\sqrt{3})-\sqrt{5}}{(\sqrt{2}+\sqrt{3})-\sqrt{5}} = \dfrac{\sqrt{2}+\sqrt{3}-\sqrt{5}}{2\sqrt{6}}$ Can you take it from here?
Yes, I get do the rest now, thank you very much!
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