Hello math123xIf these equations are going to have exact solutions, and will have to be perfect squares. A little thought will show you that the only perfect squares that are about the right size are and .

and gives the solution. Just trial and error, I'm afraid.

The only other way would be to eliminate , say, and solve the equation for . But it's a quartic:

and I don't like the look of it! (But you can check that is a solution if you like!)

Grandad