Find an equation that represents the locus of points equidistant from the lines whose equations are y = 3x + 8 and y = 3x - 6?
For equations like
y= mx+ c
c is the y- intercept (value of y at x=0)
y = 3x + 8 and y = 3x - 6
thus y interceept of our two lines are 8 and (-6)
So if we want a point on y axis equidistant from these lines
we need to have a value of y-intercept in between them
-- this means the value of y at x=0 of our answer should be in between 8 and (-6)
And the line should be parralel so that its equidistant throughout (see the attatchment)
thus answer is