Find an equation that represents the locus of points equidistant from the lines whose equations arey= 3x+ 8 andy= 3x - 6?

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- Feb 10th 2009, 09:09 PMmagentaritaLocus of Points
Find an equation that represents the locus of points equidistant from the lines whose equations are

*y*= 3*x*+ 8 and*y*= 3x - 6? - Feb 10th 2009, 09:44 PMADARSH
For equations like

y= mx+ c

c is the y- intercept (value of y at x=0)

*y*= 3*x*+ 8 and*y*= 3x - 6

thus y interceept of our two lines are 8 and (-6)

So if we want a point on y axis equidistant from these lines

we need to have a value of y-intercept in between them

-- this means the value of y at x=0 of our answer should be in between 8 and (-6)

And the line should be parralel so that its equidistant throughout (see the attatchment)

$\displaystyle

y=3x+\frac{8+(-6)}{2}

$

thus answer is

$\displaystyle y=3x+1$ - Feb 12th 2009, 06:06 PMmagentaritaVery easy......