is weight ... force due to gravity
let = the additional mass (in grams) required ...
divide the 2nd equation by the first ...
solve the last equation for
Can someone guide me through this problem:
2. A mass of 500 g stretches a spring 8.0 cm when it is attached to it.
What additional weight would you have to add to it so that the spring is stretched 10 cm?
I tried plugging in numbers into the rule and that didn't lead me anywhere!
As stated, the equation for Hooke's Law can be rewritten as follows:
The gravitational constant is substituted for acceleration , represents the spring constant, and is the displacement (distance stretched in meters).
Rearrange in terms of and solve:
Now rewrite the equation in its standard form and evaluate using the new length.
The rest is pretty straight-forward, just remember that weight is a measure of gravitational force and mind your significant figures (2).
- The tension in an elastic string is proportional to its extension.
In other words, if you double one, you double the other; if you increase one by 50%, you increase the other by 50%, and so on.
You want to increase the extension from 8 cm to 10 cm; in other words, by 25%. So increase the tension by 25% as well. Put on an extra mass of 25% of 500 gm. In other words, you'll need an extra 125 gm.
That was easy, wasn't it?
Well, you can solve it using common sense. But using formula, and understand enable you to solve any question.
500g=8k (1) initial condition
let say the weight to strecth the spring 10cm is M
you will get M = 625g
so it will require additional 125g
Of course, I'm not suggesting that you should always forget the formula. But you should always look for a simple approach first! When solving a quadratic, for example, always try to factorise before reaching for the formula.
I think your approach is kind of long winded.
For this case, F=-kx=mg
it is obviously seen that g and k are constant when compare the two situation since g is 9.81m/s^2 while k=spring constant. (since using the same spring, this vqlue should be the same for both)
So from this, we can deduce that m is directly proportional to x.
use this relation would be much faster.
instead you plug in the value into the formula compute, and then reverse it. of course it is not wrong, just kind of wasting time.
While my approach/explanation may be kind of "long winded" for people who have already had advanced math/physics classes, it is obvious the OP did not follow the rationale of using a proportion, nor did the OP understand the concept of Hooke's Law; i.e. the difference between mass and weight (hence the reason I included all of the units).
Furthermore, it is my opinion that this is not a forum to merely supply answers for a student's homework problems, but a place to further their understanding of the concept(s) and reinforce proper methods in preparation for higher level courses.
If the OP, or anyone for that matter, wants to be successful in advanced physics, it is a good idea to develop sound habits for problem solving from the beginning - because the concepts, equations, and methods only become more complex and involved.
I agree must understand the concept for problem solving. I just try to provide alternative, easier way to solve. Reduce it to the simplest form then only plug in the value. Too many value will sometimes lead to careless, besides need to take care about significant figures and decimal places all.it is a good idea to develop sound habits for problem solving from the beginning - because the concepts, equations, and methods only become more complex and involved.
First easiest way to do it is to first get all your units in their easiest form in canada on the end of year exam they usually ask you use kg-m-N
500g becomes .5kg -- F=mg F=.5(9.8) = 4.9N
80cm becomes .08m
so now using the rule F=kx you need
Force in N=force constant N/m * displacement in m
4.9N = k * .08m
It is the same spring so same K value, we are now given a new displlacement
x=10cm = .1m
With this info we can find the Force
Now that we have the new force you can get the total weight
that is the total weight they asked you how much was added on so just take your total weight and substract your initial weight
.625-.5= .125kg which is your answer
and thats that. the way your expected to do it on governement exam in june