Draw all three graphs together on one xy axis. The shaded area will be the area bounded by all three functions based on the conditions given for each function. So,
is a parabola with its vertex at the origin and compressed towards the y axis by a factor of 4 (FYI, a coefficient > 1 on your term of a parabola makes it skinnier, a coefficient <1 makes the graph wider)
The shaded area will be below this equation will be the entire graph except for what is inside the parabola.
BUT, you aren't done yet!!
Now graph the second equation right on top of the first. 6 - 2x is a line with a slope of -2 and a y-intercept of 6. Graph it and find the area where y it. If the line were by itself, the entire left side of the graph of that line would be shaded. BUT!!!! Since the conditions for the parabola must also be met, the graph of the line on top of the parabola will not allow the area inside of the parabola to be shaded.
BUT, you aren't done yet!!!
The last condition is that x 0. SOOOOO, you know what x = 0 looks like. So where on this graph satisfies all three of your given conditions?
The area under the parabola, under the line and to the right of x=0
Can you see it now? Hope that helps! Good luck!