Are you sure the answer is correct? Anyway, I will show you my method and you compare it.

then,

After which,

Finally,

You arrive at the answer,

This may be wrong.

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- Jan 27th 2009, 07:46 PM #1

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## Need help with log question?

I was doing practice exams and I got stuck on this question?

Solve for x in the equation: 2a^x = b^(x+1)

I tried it over and over and still can't get x by itself, how do you do this question? It's on the no calculator section.

The answer's x = (log2 - log b) / (log b - log a)

If it helps.

- Jan 28th 2009, 04:37 AM #2

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- Jan 28th 2009, 06:13 AM #3

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