Are you sure the answer is correct? Anyway, I will show you my method and you compare it.

then,

After which,

Finally,

You arrive at the answer,

This may be wrong.

Results 1 to 3 of 3

- January 27th 2009, 07:46 PM #1

- Joined
- Jan 2009
- Posts
- 1

## Need help with log question?

I was doing practice exams and I got stuck on this question?

Solve for x in the equation: 2a^x = b^(x+1)

I tried it over and over and still can't get x by itself, how do you do this question? It's on the no calculator section.

The answer's x = (log2 - log b) / (log b - log a)

If it helps.

- January 28th 2009, 04:37 AM #2

- Joined
- Jan 2009
- Posts
- 8

- January 28th 2009, 06:13 AM #3

- Joined
- May 2006
- From
- Lexington, MA (USA)
- Posts
- 12,026
- Thanks
- 845