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Math Help - Please Help, Hard Question for me.

  1. #1
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    Please Help, Hard Question for me.

    Hi, been having problems with these questions.. I got to be honest.. I need this to help me get through my college course, but it's a high school question.. just find it really hard.. thanks in advance:

    Question:
    1.)

    Find the equation of a straight line that passes through the point (3, -1) and is parrallel to the line y = 2x + 1. Give your answer in the form y = mx + c

    2.)

    Find the equation of a straight line that passes through the point (3, -1) and is perpendicular to the line y = 5x - 2. Give your answer in the form ax + by + c = 0

    Thanks, if I find anymore difficult.. I will shout back.

    Thanks,

    Timmy, 15
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  2. #2
    Senior Member topher0805's Avatar
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    Quote Originally Posted by Biggzi View Post
    Hi, been having problems with these questions.. I got to be honest.. I need this to help me get through my college course, but it's a high school question.. just find it really hard.. thanks in advance:

    Question:
    1.)

    Find the equation of a straight line that passes through the point (3, -1) and is parrallel to the line y = 2x + 1. Give your answer in the form y = mx + c
    If the two lines are parallel, they have the same slope. Remember that in the equation of a line (y = mx+c) , m is the slope.

    We have also been given a point on the line (3,-1) , so we need to simply plug those values into our equation to solve for c.

    <br />
-1 = 2(3) + c

    c = -7

    y = 2x - 7

    2.)

    Find the equation of a straight line that passes through the point (3, -1) and is perpendicular to the line y = 5x - 2. Give your answer in the form ax + by + c = 0

    Thanks, if I find anymore difficult.. I will shout back.

    Thanks,

    Timmy, 15
    If the lines are perpendicular, the slope is the negative reciprocal. Therefore, we can say that the slope of the line is -\frac{1}{5} . Once again we have been given a point on the line, so the rest should be straight forward.
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  3. #3
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    Thanks ever so much my friend.

    For the second equation is x +5y +8 = 0 right?
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  4. #4
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    Quote Originally Posted by Biggzi View Post
    [snip]
    2.) Find the equation of a straight line that passes through the point (3, -1) and is perpendicular to the line y = 5x - 2. Give your answer in the form ax + by + c = 0
    [snip]
    Quote Originally Posted by Biggzi View Post
    Thanks ever so much my friend.

    For the second equation is x +5y +8 = 0 right?
    Does the given point (3, -1) satisfy this equation ....?

    Check your arithmetic.
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