Q: Factorize 51y^2 - 2580y - 39879.

Please help if you can.

Many thanks.

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- Jan 20th 2009, 05:52 AMisuckatmathsI hate Factorization!
Q: Factorize 51y^2 - 2580y - 39879.

Please help if you can.

Many thanks. - Jan 20th 2009, 06:31 AMprincess_21
Simplifying

51y2 -2580y -39879

First, you need to reorder the terms then factor the GCF that will be 3

3(-13293 + -860y + 17y2)

then factor a trinomial

3[(-211 -17y)(63 -y)]so the final result is3(-211-17y)(63 -y)

i'm not sure bout this. i just tried. you can check it. - Jan 20th 2009, 07:59 AMred_dog
$\displaystyle 51y^2-2580y-39879=51(y-y_1)(y-y_2)$

where $\displaystyle y_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ and $\displaystyle a=51, \ b=-2580, \ c=-39879$ - Jan 20th 2009, 08:11 AMSoroban
Hello, isuckatmaths!

This is*The Trinomial From Hell*(coming to a theater near you).

Quote:

Factor: .$\displaystyle 51y^2 - 2580y - 39879$

Factor out 3: .$\displaystyle 3(17y^2 - 860y - 13293)$

There are a number of ways to factor this ugly trinomial.

. . I hope you know at least one.

Answer: .$\displaystyle 3(x - 63)(17x + 211)$

- Jan 20th 2009, 08:15 AMprincess_21