1. ## Physics

I wanted someone to look over my work to see if my answers are correct.

Thank You!

A bicyclist is finishing his repair of a flat tire when a friend rides by with a constant speed of 3.5m/s. Two seconds later the bicylicts hops on his bike and accelerates at 2.4m/s^2 until he catches his friend.
(a) How much time does it take until he catches his friend?
(b) How far has he traveled in this time?
(c) What is his speed when he catches up?

2. for (a) , I get $\displaystyle t = 6.28$ sec from the time his friend passes him

(b) $\displaystyle \Delta x = \frac{1}{2}(2.4)(t-2)^2 \approx 22 \, m$

(c) $\displaystyle v_f = (2.4)(t-2) \approx 10.3 \, m/s$

3. ## RE:

Uhh yes you are right. I just happened to accidentally forget to plug my time into the (t-2) equation. I just inserted it.

Thank You so Much!!

4. ## RE:

Also I have another question is reference to this problem. Anytime the question says "catches up" is that always subtraction? In our case (t-2). How could this question be worded to where they would give me an addition such as (t+2)?

Thanks,
qbkr21