A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.60 later.

What is the rocket's acceleration?

Let accln. of the rocket=a

velocity of Bolt= velocity of rocket after 4 sec.= 4a .............upwards.................first eq of kinematics...

dist. covered by rocket in 4 sec.= 1/2 XaX 4X4= 8a ................................second eq of kinematics

now the Bolt falls from this height(8a) with accln. due to gravity in 6.6sec.

second eq of kinematics

s=ut-1/2 g t^2 .............................free fall

8a= 4a-1/2 X (9.8 X6.6X6.6)

solve this......