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Math Help - 1-D Kinematics Problem

  1. #1
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    1-D Kinematics Problem

    I'm having trouble with this problem.

    A car starts from rest at a stop sign. It accelerates at 4.4 for 6.2 , coasts for 2.5 , and then slows down at a rate of 3.4 for the next stop sign. How far apart are the stop signs?



    Any help is appreciated.
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  2. #2
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    A car starts from rest at a stop sign. It accelerates at 4.4 for 6.2 , coasts for 2.5 , and then slows down at a rate of 3.4 for the next stop sign. How far apart are the stop signs?


    whole distance can be divided into 3 parts
    dis. coverd during first 6.2 sec=S1 = 1/2 at^2 = 1/2 X 4.4 X 6.2 X 6.2 =84.56 m ......... second eq. of kinematics

    velocityafter 6.2 sec.=V= 0+at =6.2X4.4=27.28m/sec. ............. first eq. of kinematics

    now the car moves at this speed for next 2.5 sec.
    dist coverd= S2=Vt=(6.2X4.4)X2.5 = 68.2m ........dist= speedXtime

    now the car slows down fro V to zero at the rate 3.4m/sec sq

    distance covered S3=√ [(V^2-U^2)/2a] ............ third eq. of kinematics
    =[6.2X4.4]/√6.8 = 10.46m


    S1+ S2+ S3
    Last edited by sumit2009; January 19th 2009 at 08:38 AM.
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  3. #3
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    Thanks alot! I got an answer of approximately 2.6 x 10^2 meters . Appreciate it!
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