Hey guys! I have a question about one of these physics problems..
The notorious 'Dr. B' is dropped from the top of a building by a group of disgruntled students. Some stories below, Dr. B's body is observed to pass by a window 2.0 m tall in 0.15 s. What is the average speed of Dr. B's body as it passes by the window?
This is part one, and I'm sure it's 2.0/.15 = 13.33333333m/s, However, part two I'm really confused on what to do. It states:
From how far above the window was Dr. B's body dropped?
I have.. Final Velo = 13.33333333, time = .15s, I'm assuming initial velo = 0
So I'm thinking I use d=(vi+vf)/2 *t where vi and vf are initial and final velocity.
Doing that I get .9999999998. I'm assuming I need to use g = 9.80 somewhere in there.... Is that right or is there something I'm missing?