Back with more Qs^^
without calculator
solve for x :
logx = 3loga - logb +logc the answer is a^3c/b
i canceled all the logs and got x =a^3-b+c than i got stuck
simplify:
4^log2 3
i got to 3=2X than i got stuck the answer is 9... 3/2 can't get 9..
whats the value of X :
logx 8=3/4
32=3^x stuck
how can a square root b/c^2 = loga+1/2logb-2logc ?( can't find the root key on the keyboard>.<)
ty
tyyy
i didnt know that u can multiply the 3^2 and that formula >.<
for number 3) whats that index form? is it the exponential form?
x^3/4 =8
3/4logx=8
3logx=32
stuck again the answer is 16
4)
how can "A"root b/c^2 = loga+1/2logb-2logc?
got a few more
5)given log80 = a which of the following is an expression for log2 in terms of a
answer is a-1/3 (why)
6) solve log2 x=log4 x^2
answer is all real numbers(why)
7) solve 1/log2 x + 1/log8 x =2
helpp
Can anyone also tell me the difference between evaluate and solve?
solve is to solve for x but i dont know what evaluate is really looking for ty