what is 2^(4-1)^2 ?

(2 raised to (4-1) raised to 2)

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- Jan 8th 2009, 10:49 AMvscidexponent confusion
what is 2^(4-1)^2 ?

(2 raised to (4-1) raised to 2) - Jan 8th 2009, 11:04 AMmasters
- Jan 8th 2009, 11:11 AMvscid
- Jan 8th 2009, 11:18 AMmasters
- Jan 8th 2009, 11:23 AMvscid
- Jan 8th 2009, 06:12 PMHallsofIvy
which is . That is true because

However, which is how what you wrote should be interpreted, is equal to - Jan 8th 2009, 08:01 PMvscid
- Jan 8th 2009, 08:30 PMmr fantastic
- Jan 9th 2009, 05:51 AMvscid
- Jan 9th 2009, 09:09 AMmasters
The rule is when you take a power to a power you multiply the exponents:

Yours was a special case. Not only did you want to take the base to a power, you also wanted to take the power to a power.

In this case you must work from the top down. If you were putting this in a calculator you would have to enter it this way:

2^(3^2) = 512

The parentheses tell the calculator to perform this operation first to get 9, then take 2 to the 9th power to get 512.

If you entered it 2^3^2, you would get 64 because the calculator performs the operations from left to right: 2^3 is 8 and 8^2 is 64.

It's a little tricky when you stack exponents. Just remember to start at the top and work your way down.

Good luck. - Jan 9th 2009, 10:49 AMvscid
Above you have written: 2^(3^2) = 512.

I do not have the parenthesis in red in my original post. In fact, I should say I have no parenthesis (besides the inevitable (4-1) )

So it is actually 2^3^2.

My question was, if there are no parenthesis as above, then the value will be 2^9 right?