Vector 1: x=0, y = 60A plane flies 60km due north then makes a 40° turn west and flies another 30 km. The pilots makes a 2nd 40° turn west and lands 50km later. USe vector components to find the planes displacement.

Vector 2: x=30cos40=-22.98, y= 30sin40=19.28

Vector 3: x=50cos40=-38.30, y=50sin40=32.14

Adding all the Xs up I get 61.28 and for y 82.42

To find displacement I do 82.42/61.28=tan theta

tan^-1(82.42/61.28)=52.37

180-42-37=127°

So displacement would be 127°?