If t1 = 6, t2 = 4, t3 = 2, and tn = (tn-1 + tn-2) x tn-1, find t7.
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Originally Posted by casey_k If t1 = 6, t2 = 4, t3 = 2, and tn = (tn-1 + tn-2) x tn-1, find t7. Are you sure you typed the question correctly? According to your recursive equation you get:
the sequence is 6, 4, 2 the recursive formula is tn = (tn-3 + tn-2) x tn-1 so I did it = (2+4) x 6 = 36 and i got 2,068, 416 for t7 but it's not right and now i'm not sure how to solve it.
Originally Posted by casey_k If t1 = 6, t2 = 4, t3 = 2, and tn = (tn-1 + tn-2) x tn-1, find t7. I'm guessing here, but is this your equation?
Sorry I didn't post my question clearly, still getting the hang of codes.
Originally Posted by casey_k Sorry I didn't post my question clearly, still getting the hang of codes. Using this equation I've got:
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