If t1 = 6, t2 = 4, t3 = 2, and tn = (tn-1 + tn-2) x tn-1, find t7.

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- Jan 4th 2009, 11:58 AMcasey_kSequences
If t1 = 6, t2 = 4, t3 = 2, and tn = (tn-1 + tn-2) x tn-1, find t7.

- Jan 4th 2009, 12:26 PMearboth
- Jan 4th 2009, 12:36 PMcasey_kRe:
the sequence is 6, 4, 2

the recursive formula is tn = (tn-3 + tn-2) x tn-1

so I did it = (2+4) x 6 = 36

and i got 2,068, 416 for t7

but it's not right and now i'm not sure how to solve it. (Doh) - Jan 4th 2009, 01:40 PMskeeter
- Jan 4th 2009, 01:42 PMcasey_kFormula

Sorry I didn't post my question clearly, still getting the hang of codes. - Jan 5th 2009, 03:06 AMearboth