If t1 = 6, t2 = 4, t3 = 2, and tn = (tn-1 + tn-2) x tn-1, find t7.

Printable View

- January 4th 2009, 11:58 AMcasey_kSequences
If t1 = 6, t2 = 4, t3 = 2, and tn = (tn-1 + tn-2) x tn-1, find t7.

- January 4th 2009, 12:26 PMearboth
- January 4th 2009, 12:36 PMcasey_kRe:
the sequence is 6, 4, 2

the recursive formula is tn = (tn-3 + tn-2) x tn-1

so I did it = (2+4) x 6 = 36

and i got 2,068, 416 for t7

but it's not right and now i'm not sure how to solve it. (Doh) - January 4th 2009, 01:40 PMskeeter
- January 4th 2009, 01:42 PMcasey_kFormula

Sorry I didn't post my question clearly, still getting the hang of codes. - January 5th 2009, 03:06 AMearboth