The reaction is:
PCl5 <---> PCl3 + Cl2
At equilibrium: PCl5=(4.3 x 10^-4) PCl3 =0.014 Cl2= 0.014
Therefore,
Equilibrium constant K
= 0.014 x 0.014/(4.3 x 10^-4)
= 0.000196/(4.3 x 10^-4)
=0.4558
1. what is the value of the equilibrium constant at for the decomposition of phosporus pentachloride gas to phosphorus trichloride gas and chlorine gas? At equilibrium,
4. In the haber process of synthesizing ammonia, the value of K is for the reaction at . In a sealed container at equilibrium at the concentations of and are measured to be 0.50 mol/L and 1.50mol/L respectively. Write the equilibrium constant equation and calculate the equilibreum concentration of )
The reaction is:
PCl5 <---> PCl3 + Cl2
At equilibrium: PCl5=(4.3 x 10^-4) PCl3 =0.014 Cl2= 0.014
Therefore,
Equilibrium constant K
= 0.014 x 0.014/(4.3 x 10^-4)
= 0.000196/(4.3 x 10^-4)
=0.4558
N2 + 3H2 <---> 2NH34. In the haber process of synthesizing ammonia, the value of K is for the reaction at . In a sealed container at equilibrium at the concentations of and are measured to be 0.50 mol/L and 1.50mol/L respectively. Write the equilibrium constant equation and calculate the equilibreum concentration of )
Equilibrium concentration: [H2] = 0.50 M, [N2] = 1.50 M
Let the equilibrium concentration of NH3 be x M
Therefore,
Equilibrium constant equation: (By law of mass action)
K = [NH3]^2/([H2]^3 x [N2])
8 x 10^-7 = x^2/((0.5)^3 x (1.5))
x^2 = (8 x 10^-7) x (0.125) x (1.5)
x^2 = 1.5 x 10^-7
x = 3.87 x 10^-4
Can you quote the exact lines please?
EDIT:
By the Gulbarg-Waage law of mass action:
For a reaction:
where, [S], [T], [A], [B] are equlibrium concentrations and α,β, σ, τ are molar coefficients(number of moles of the particular element or compound, for example, σ moles of S are formed in the above equation)
Now, since, therefore as the required reaction also takes place at 400 degree celsius, we can use the above value of K and plug it into the equilibrium constant equation. Then all I have done is some cross multiplication(using the given values) to get concentration of NH3(which I assumed to be x moles/L)the value of K is 8 x 10^-7 for the reaction at 400 degree celsius