The diagram shows a case of mass 15kg being dragged along a rough horizontal floor by means of a strap inclined at an angle A to the horizontal, where sinA = 0.6
The tension in the strap is 50N. the coefficient of friction between the case and the floor is 0.25
Modelling the case as a particle,
a) show that the normal reaction between the case and the floor has magnitude 117N,
b) find, to two decimal places, the acceleration of the case.
I have tried F=0.25*(15*0.8) + 50*0.6
this is Friction = coefficient*reaction + 50sinA
Ive no idea if this is the correct thing to do though. I get friction=66.75.
What do i do next though??