1. ## Mechanics / physics

The diagram shows four coplanar forces of magnitude SN, RN, 60N and 80N acting at a point 0 in the direction shown.

Given the forces are in equilibrium, find the values of R and S.

I try to solve S

SNCOS60 = 60N
SN = 60/cos60
SN =120N

Try to solve R

RN + 120sin60 = 80N
RN = 80 - 120sin60
RN = -23.92

Can anybody spot a mistake? I'm sure you use SIN for forces up and down and COS for forces horizontally.

2. looking at it again would i find RN using 120sin30 ?

3. what diagram?

4. Its this 1

seem this site doesnt host pictures for long lol

5. Originally Posted by djmccabie
Its this 1

seem this site doesnt host pictures for long lol
$\displaystyle S \cos 30^0 = 60$ .... (1)

$\displaystyle R + S \sin 30^0 = 80$ .... (2)

Solve equations (1) and (2).

6. Originally Posted by djmccabie
Its this 1

seem this site doesnt host pictures for long lol

http://www.mathhelpforum.com/math-he...-question.html

7. As all forces are acting at one point, and that the point is being held in equilibrium by these forces it is said that the opposite forces are of equal magnitude. Mr Fantastic has detailed this with the two equations for vertical and horzontal force.

Since

S = (60/cos30)

Then

2R = 160-S

This can be simplified to be....

R = 80 - (30/cos30)

Kind Regards,

Ross