looking at it again would i find RN using 120sin30 ?
The diagram shows four coplanar forces of magnitude SN, RN, 60N and 80N acting at a point 0 in the direction shown.
Given the forces are in equilibrium, find the values of R and S.
I try to solve S
SNCOS60 = 60N
SN = 60/cos60
SN =120N
Try to solve R
RN + 120sin60 = 80N
RN = 80 - 120sin60
RN = -23.92
Can anybody spot a mistake? I'm sure you use SIN for forces up and down and COS for forces horizontally.
might be because you posted it on your other thread ...
http://www.mathhelpforum.com/math-he...-question.html
As all forces are acting at one point, and that the point is being held in equilibrium by these forces it is said that the opposite forces are of equal magnitude. Mr Fantastic has detailed this with the two equations for vertical and horzontal force.
Since
S = (60/cos30)
Then
2R = 160-S
This can be simplified to be....
R = 80 - (30/cos30)
Kind Regards,
Ross