Results 1 to 5 of 5

Math Help - Help with finding Annual Rate of Increase/Decrease

  1. #1
    Newbie
    Joined
    Nov 2008
    Posts
    8

    Help with finding Annual Rate of Increase/Decrease

    Data table in attachment.

    Determine, to the nearest tenth of a percent, the average annual rate of increase/decrease for each school.
    I really have no clue what to do here. It's related to Exponents/Logs I'm pretty sure, I didn't do so hot in that unit.. Any help would be awesome.
    Attached Thumbnails Attached Thumbnails Help with finding Annual Rate of Increase/Decrease-schoolpoptable.jpg  
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
    Posts
    11,740
    Thanks
    645
    Hello, fkhnksaha!

    It's much simpler than you think . . .


    Determine, to the nearest tenth of a percent,
    the annual rate of increase/decrease for each school.

    . . \begin{array}{|c|c|c|} \text{Year} & \text{School \#1} & \text{School \#2} \\ \hline 1995 & 1353 & 449 \\ 1996 & 1391 & 517 \\ 1997 & 1343 & 519 \\ 1998 & 1142 & 518 \\ 1999 & 1167 & 574 \\ 2000 & 1087 & 620 \\ 2001 & 999 & 635 \\ 2002 & 862 & 605 \\ 2003 & 818 & 619 \end{array}

    Formula: . \frac{x_2-x_1}{x_1} . . . and convert to a percent.


    . . In baby-talk: the second term minus the first, divided by the first.



    School #1


    Year 1995-1996: 1353 → 1391

    . . We have: . \frac{1391-1353}{1353} \:=\:\frac{38}{1353} \:=\:0.028085735

    Therefore, the rate of increase is: . 2.8\%



    Year 1996-1997: 1391 → 1343

    . . We have: . \frac{1343-1391}{1391} \:=\:\frac{-50}{1393} \:=\:-0.035945363

    Therefore, the rate of decrease is: . -3.6\%



    Think you can do the rest of them now?

    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Nov 2008
    Posts
    8
    Oh my, I feel stupid right now. I guess groups of questions aren't always related. Thanks for helping me realize the simplicity of it, Soroban.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Newbie
    Joined
    Dec 2008
    Posts
    3
    To find the average do we just take the rate of increase/decrease of each year, add them, then divide by number of terms?
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Newbie
    Joined
    Nov 2008
    Posts
    8
    Quote Originally Posted by yaphetkotto View Post
    To find the average do we just take the rate of increase/decrease of each year, add them, then divide by number of terms?
    That's what I would do.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 3
    Last Post: April 26th 2010, 09:30 AM
  2. Finding Intervals of increase and decrease
    Posted in the Calculus Forum
    Replies: 2
    Last Post: April 6th 2010, 10:20 AM
  3. Replies: 2
    Last Post: May 5th 2009, 12:56 PM
  4. Finding Percentage increase and decrease
    Posted in the Algebra Forum
    Replies: 1
    Last Post: February 2nd 2009, 10:17 PM
  5. Replies: 1
    Last Post: January 28th 2009, 02:43 AM

Search Tags


/mathhelpforum @mathhelpforum