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Math Help - A game is played with a deck of ten cards...

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    A game is played with a deck of ten cards...

    A game is played with a deck of ten cards numbered from 1 to 10. Shuffle the deck thoroughly. Take the top card. If it is numbered one, you win. If it in numbered k, where k>1, then replace the card into the kth positition from the top and draw again. You are allowed a maximum of 3 draws before losing the game. What is the probability of winning?

    After the 1/10 chance on the first draw, I no longer know how to solve.
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    First off, nice signature . It works quite well on the mozilla start page
    Quote Originally Posted by ceasar_19134 View Post
    A game is played with a deck of ten cards numbered from 1 to 10. Shuffle the deck thoroughly. Take the top card. If it is numbered one, you win. If it in numbered k, where k>1, then replace the card into the kth positition from the top and draw again. You are allowed a maximum of 3 draws before losing the game. What is the probability of winning?

    After the 1/10 chance on the first draw, I no longer know how to solve.
    So, if a 1 is on top you win, chance of this happening: 1/10

    If a 2 is on top, then you will only win if the second card is a 1, chance of this happening: 1/10*1/9=1/90

    If anything else is on top, you will only win if 1 is either the second or third card, chance of this happening is:
    (chance of second card being 1) + (chance of third card being one)
    = (8/10 * 1/9) + (8/10 * 7/9 * 1/8)
    = 8/90 + 7/90
    = 15/90

    Add all those together to get:
    9/90+1/90+15/90=25/90=5/14

    But make sure to CHECK MY ARITHMETIC!!!!!!!!!!!
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