If a wheel rolls exactly 5 revolutions while rolling 80pi feet, what is the diameter of the wheel?
I think the answer is .64, but I want to make sure I'm doing it right, or see how to do it if I'm wrong.
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If a wheel rolls exactly 5 revolutions while rolling 80pi feet, what is the diameter of the wheel?
I think the answer is .64, but I want to make sure I'm doing it right, or see how to do it if I'm wrong.
If a wheel rolls without slipping its center will move the same distance as the circumference has traced out. Since C = (pi)d if we know that the wheel has rolled 5 revolutions it has rolled 5*C = 5(pi)d = 80(pi) ft.Quote:
Originally Posted by ceasar_19134
Thus d = 16 ft.
-Dan