The height h of an equilateral triangle is twice its base. Find the radius of the circle inscribed. *show working and explanation PLS
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Originally Posted by mathbuoy The height h of an equilateral triangle is twice its base. Find the radius of the circle inscribed. *show working and explanation PLS Is the question correct?? Let a is the side of an equilateral triangle.. h= Again according to question So or Am i going wrong somewhere?? But you can use where A,B,C are angles of a triangle, a,b,c are sides of triangle
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Originally Posted by mathbuoy The height h of an equilateral triangle is twice its base. Find the radius of the circle inscribed. *show working and explanation PLS bogus question ... the height of an equilateral triangle cannot be twice the length of its base. recheck the exact statement of the problem.
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