1. ## determine the rAdius

The height h of an equilateral triangle is twice its base.
Find the radius of the circle inscribed.

*show working and explanation PLS

2. Originally Posted by mathbuoy
The height h of an equilateral triangle is twice its base.
Find the radius of the circle inscribed.

*show working and explanation PLS
Is the question correct??

Let a is the side of an equilateral triangle..

h=$\displaystyle \frac{\sqrt{3}}{2}a$
Again according to question $\displaystyle h=2a$

So $\displaystyle \frac{\sqrt{3}}{2}a=2a$

or $\displaystyle \sqrt{3}=4$

Am i going wrong somewhere??

But you can use $\displaystyle \frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}=2R$

where A,B,C are angles of a triangle,
a,b,c are sides of triangle

3. hope this helps

4. Originally Posted by mathbuoy
The height h of an equilateral triangle is twice its base.
Find the radius of the circle inscribed.

*show working and explanation PLS
bogus question ... the height of an equilateral triangle cannot be twice the length of its base.

recheck the exact statement of the problem.