The height h of an equilateral triangle is twice its base.
Find the radius of the circle inscribed.
*show working and explanation PLS
Is the question correct??
Let a is the side of an equilateral triangle..
h=$\displaystyle \frac{\sqrt{3}}{2}a$
Again according to question $\displaystyle h=2a$
So $\displaystyle \frac{\sqrt{3}}{2}a=2a$
or $\displaystyle \sqrt{3}=4$
Am i going wrong somewhere??
But you can use $\displaystyle \frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}=2R $
where A,B,C are angles of a triangle,
a,b,c are sides of triangle