Thread: Solving Trigonometric Equations (Advanced Functions)

Determine the solution for this equation on the interval [ 0 is less or equal to x which is less than or equal to 2pi ] :

sin2x = 1/√2

How do you solve this question? We are supposed to solve for x and then graph it where sin will be positive or negative... I understand how to do equations with the simple trig functions, but not with the compound angle formulae...

If anyone could help me out with this question, that would be wonderful!!

double post ...

http://www.mathhelpforum.com/math-he...functions.html