Determine the solution for this equation on the interval [ 0 is less or equal to x which is less than or equal to 2pi ] :
sin2x = 1/√2
How do you solve this question? We are supposed to solve for x and then graph it where sin will be positive or negative... I understand how to do equations with the simple trig functions, but not with the compound angle formulae...
If anyone could help me out with this question, that would be wonderful!! :)