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Math Help - Parabola Q?

  1. #1
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    Parabola Q?

    I require help graphing the parabola y^2=-4x. Also, what will the focus be?

    TIA
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  2. #2
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    Quote Originally Posted by 300C View Post
    I require help graphing the parabola y^2=-4x. Also, what will the focus be?

    TIA

    =============================================
    300C,
    standard from is x = a [( y-k)^2] + h
    If a<0, it opens to left horizontally.
    where, Focus point is { [ h+ (1/4a)], k }
    Rewrite your question to standard from and get
    x = (- 1/4) [ ( y-0)^2 ] + 0
    where you see a = -1/4, k=0, h=0
    Now Focust point is ([ h+ (1/4a)] ,0 )
    Solve [ h+ 1/(4a) ] by substitue a = -1/4 and get -1
    so Focusto points =( -1, 0 )
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