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Math Help - Working with scientific notation

  1. #1
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    Working with scientific notation

    This is part of a Chemical Equilibrium question and I'm just a bit stuck on how to work out the problem with scientific notation and my calculator..

    (3.1 x 10tothepower -2)to be squared
    --------------------------------------
    (8.5 x 10tothepower -1) x (3.1 x 10tothepower -3)to be cubed


    I have the answer in my worksheet but I'm unsure of how it was got. I have tried but I got a completely different answer (0.12156...)

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  2. #2
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    Quote Originally Posted by Larianne View Post
    This is part of a Chemical Equilibrium question and I'm just a bit stuck on how to work out the problem with scientific notation and my calculator..

    (3.1 x 10tothepower -2)to be squared
    --------------------------------------
    (8.5 x 10tothepower -1) x (3.1 x 10tothepower -3)to be cubed


    I have the answer in my worksheet but I'm unsure of how it was got. I have tried but I got a completely different answer (0.12156...)

    =\frac{(3.1 \times 10^{-2})^2}{(8.5 \times 10^{-1})(3.1 \times 10^{-3})^3}

    =\frac{(3.1)^2 \times 10^{-4}}{8.5 \times 10^{-1}\times(3.1)^3 \times 10^{-9}}

    =\frac{10^{-4}}{8.5 \times3.1 \times 10^{-10}}

    =\frac{10^{6}}{8.5 \times3.1 }

    now, can you simplify further ???
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  3. #3
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    Quote Originally Posted by Shyam View Post
    =\frac{(3.1 \times 10^{-2})^2}{(8.5 \times 10^{-1})(3.1 \times 10^{-3})^3}

    =\frac{(3.1)^2 \times 10^{-4}}{8.5 \times 10^{-1}\times(3.1)^3 \times 10^{-9}}

    =\frac{10^{-4}}{8.5 \times3.1 \times 10^{-10}}

    =\frac{10^{6}}{8.5 \times3.1 }

    now, can you simplify further ???
    Thanks for your reply.

    Is that the best method when dealing with these types of questions- to separate the powers?

    The answer I get is 37950.664

    The answer in the worksheet is 3.8 x 10tothepowerof4. So because the question started with the scientific notation you can put the answer back in like that. If that makes any sense???
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