# Math Help - Quadratci function graph, and a thank you

1. ## Quadratci function graph, and a thank you

Hey guys, I just want to thank all of you for all the help you have been providing. Just seeing all the steps, and how they are related to the answer is phenomenal. Some of my questions may seem petty and simple, but it really makes all the difference in the world so thank you:P

The graph of a quadratic function "f" is the graph of y=-2x^2 translated 4 units to the left and 6 units down. What is the equation of function?

2. Originally Posted by mcinnes
Hey guys, I just want to thank all of you for all the help you have been providing. Just seeing all the steps, and how they are related to the answer is phenomenal. Some of my questions may seem petty and simple, but it really makes all the difference in the world so thank you:P

The graph of a quadratic function "f" is the graph of y=-2x^2 translated 4 units to the left and 6 units down. What is the equation of function?
$y = -2(x+4)^2 - 6$

3. Originally Posted by mcinnes
Hey guys, I just want to thank all of you for all the help you have been providing. Just seeing all the steps, and how they are related to the answer is phenomenal. Some of my questions may seem petty and simple, but it really makes all the difference in the world so thank you:P

The graph of a quadratic function "f" is the graph of y=-2x^2 translated 4 units to the left and 6 units down. What is the equation of function?
You're welcome, mcinnes. We do what we can.

Now, for your translation. Are we translating $y=-2x^2$ or has it already been translated and we're looking for the equation of the pre-image?

If we're translating this guy, the new equation would be $y=-2(x+4)^2-6$

If $y=-2x^2$ is the equation of the image after translation, then the pre-image equation would be $y=-2(x+4)^2+6$