If I have the following relationships:

AA=2
AB=3
AC=5
BB=4
BC=6
BD=10
CC=8
CD=12
DD=16

How do I break down each expression A,B,C,D so that I can put together each factor and get the correct value. For example A=x, B=y =>x+y=3

2. Originally Posted by Mathdude123
If I have the following relationships:

AA=2
AB=3
AC=5
BB=4
BC=6
BD=10
CC=8
CD=12
DD=16

How do I break down each expression A,B,C,D so that I can put together each factor and get the correct value. For example A=x, B=y =>x+y=3
1. Probably you've noticed that

AA = 2; BB = 4; CC = 8; DD = 16; .... obviously $2^n$

2. If you set A = 1, B = 2, C = 4, D = 8 then the relation XY = x + y

3. Thank you, it was a stupid question, Ive got it now!