If I have the following relationships: AA=2 AB=3 AC=5 AD=9 BB=4 BC=6 BD=10 CC=8 CD=12 DD=16 How do I break down each expression A,B,C,D so that I can put together each factor and get the correct value. For example A=x, B=y =>x+y=3
Last edited by Mathdude123; November 22nd 2008 at 06:07 AM.
Follow Math Help Forum on Facebook and Google+
Originally Posted by Mathdude123 If I have the following relationships: AA=2 AB=3 AC=5 AD=9 BB=4 BC=6 BD=10 CC=8 CD=12 DD=16 How do I break down each expression A,B,C,D so that I can put together each factor and get the correct value. For example A=x, B=y =>x+y=3 1. Probably you've noticed that AA = 2; BB = 4; CC = 8; DD = 16; .... obviously 2. If you set A = 1, B = 2, C = 4, D = 8 then the relation XY = x + y
Thank you, it was a stupid question, Ive got it now!
Last edited by Mathdude123; November 22nd 2008 at 11:45 AM.
View Tag Cloud