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Math Help - Urgent, please help!!

  1. #1
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    Urgent, please help!!

    If I have the following relationships:

    AA=2
    AB=3
    AC=5
    AD=9
    BB=4
    BC=6
    BD=10
    CC=8
    CD=12
    DD=16

    How do I break down each expression A,B,C,D so that I can put together each factor and get the correct value. For example A=x, B=y =>x+y=3
    Last edited by Mathdude123; November 22nd 2008 at 05:07 AM.
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  2. #2
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    earboth's Avatar
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    Quote Originally Posted by Mathdude123 View Post
    If I have the following relationships:

    AA=2
    AB=3
    AC=5
    AD=9
    BB=4
    BC=6
    BD=10
    CC=8
    CD=12
    DD=16

    How do I break down each expression A,B,C,D so that I can put together each factor and get the correct value. For example A=x, B=y =>x+y=3
    1. Probably you've noticed that

    AA = 2; BB = 4; CC = 8; DD = 16; .... obviously 2^n

    2. If you set A = 1, B = 2, C = 4, D = 8 then the relation XY = x + y
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  3. #3
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    Joined
    Nov 2008
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    Thank you, it was a stupid question, Ive got it now!
    Last edited by Mathdude123; November 22nd 2008 at 10:45 AM.
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