# Work Question - Non Mathematician

• Nov 20th 2008, 06:23 AM
simonsjd
Work Question - Non Mathematician

If you have four questions to be answered together. Each answer can have twenty possible answers and all the answers can have two sub conditions, how many different combination of answers can you get.

Thanks
• Nov 20th 2008, 07:10 AM
ILoveMaths07
$20 \times 2 = 40$ possible answers for each question (with sub-conditions).

The first answer can be chosen in $40$ ways.

The second answer can be chosen in $40$ ways.

The third answer can be chosen in $40$ ways.

The fourth answer can be chosen in $40$ ways.

So, total number of different combinations $= 40^4 = 2560000.$

I hope that helps. :)

me07.
• Nov 20th 2008, 07:58 AM
simonsjd
Thanks
Hi Me07
Thanks for that. Makes sense now.
Cheers