A gas sample at 23 degrees C occupies a volume of 14 L. At what temperature will it occupy 25 L?
I started by converting C to K. So 23 degrees C = 296 K.
Then I plugged the values into the equation:
V1/T1 = V2/T2
Since I am looking for T2 I change it to:
T2 = V1/T1V2
When I plug numbers in I get:
14L/(296 K)(25L) = 0.00189 K
Is this right? It doesn't seem right because the temperature is so low. Can anyone help me? Thanks sooo much.