A gas sample at 23 degrees C occupies a volume of 14 L. At what temperature will it occupy 25 L?

I started by converting C to K. So 23 degrees C = 296 K.

Then I plugged the values into the equation:

V1/T1 = V2/T2

Since I am looking for T2 I change it to:

T2 = V1/T1V2

When I plug numbers in I get:

14L/(296 K)(25L) = 0.00189 K

Is this right? It doesn't seem right because the temperature is so low. Can anyone help me? Thanks sooo much.