chemistry/math: gas equations

**daydreembelievr** · November 19th 2008, 07:03 PM

A gas sample at 23 degrees C occupies a volume of 14 L. At what temperature will it occupy 25 L?

I started by converting C to K. So 23 degrees C = 296 K.

Then I plugged the values into the equation:
V1/T1 = V2/T2

Since I am looking for T2 I change it to:
T2 = V1/T1V2

When I plug numbers in I get:

14L/(296 K)(25L) = 0.00189 K

Is this right? It doesn't seem right because the temperature is so low. Can anyone help me? Thanks sooo much.

**o_O** · November 19th 2008, 09:25 PM

You just messed up your algebra:

$\begin{aligned} \frac{V_1}{T_1} & = \frac{V_2}{T_2} \\ V_1 T_2 & = V_2 T_1 \qquad \text{Cross multiplied} \\ T_2 & = \frac{V_2 T_1}{V_1} \\ T_2 & = \frac{(25 L)[ (23 + 273 ) K]}{14 L} \end{aligned}$

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