# chemistry/math: gas equations

• November 19th 2008, 08:03 PM
daydreembelievr
chemistry/math: gas equations
A gas sample at 23 degrees C occupies a volume of 14 L. At what temperature will it occupy 25 L?

I started by converting C to K. So 23 degrees C = 296 K.

Then I plugged the values into the equation:
V1/T1 = V2/T2

Since I am looking for T2 I change it to:
T2 = V1/T1V2

When I plug numbers in I get:

14L/(296 K)(25L) = 0.00189 K

Is this right? It doesn't seem right because the temperature is so low. Can anyone help me? Thanks sooo much.
• November 19th 2008, 10:25 PM
o_O
You just messed up your algebra:

\begin{aligned} \frac{V_1}{T_1} & = \frac{V_2}{T_2} \\ V_1 T_2 & = V_2 T_1 \qquad \text{Cross multiplied} \\ T_2 & = \frac{V_2 T_1}{V_1} \\ T_2 & = \frac{(25 L)[ (23 + 273 ) K]}{14 L} \end{aligned}